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Write in reaction notation. 5Li2O

submitted by stone12345 to AskUpgoat 3.5 yearsDec 6, 2021 22:09:42 ago (+2/-0)     (AskUpgoat)

Sorry, we learned this a while back, and I have forgotten how to do this. I tried looking it up and nothing really showed up.


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[ - ] localsal 1 point 3.5 yearsDec 6, 2021 22:42:50 ago (+1/-0)

[ - ] stone12345 [op] 1 point 3.5 yearsDec 6, 2021 23:00:23 ago (+1/-0)

I'm not sure. I don't know what it wants me to do. If I had the answer I could probably figure it out. I have been searching for it for like an hour now. I am studying for a final exam for the 1st semester right now, the exam takes place tomorrow, so I am kind of running out of time. Honestly, I might just take the X on this one.

[ - ] localsal 1 point 3.5 yearsDec 6, 2021 23:08:35 ago (+1/-0)

Without more context it is a very hard question to answer.

reactions typically require 2 or more molecules, and Li2O is a single molecule.

[ - ] stone12345 [op] 1 point 3.5 yearsDec 6, 2021 23:11:16 ago (+1/-0)

Does it want me to expand it you think? Like Li2O + Li2O + Li2O + Li2O + Li2O

[ - ] localsal 1 point 3.5 yearsDec 6, 2021 23:12:43 ago (+1/-0)

That's not really a reaction. same as saying 5x2 is 2+2+2+2+2, not very helpful.

[ - ] stone12345 [op] 0 points 3.5 yearsDec 6, 2021 23:07:29 ago (+1/-1)

On the test tomorrow I'm just going to re-add them. Hopefully, that is what "reaction notation" means. Someone really needs to murder all of these Freemasons, as they are the ass-pounding faggots that are responsible for bullshit like this. Anyways, thanks, man.

[ - ] localsal 2 points 3.5 yearsDec 6, 2021 23:11:01 ago (+2/-0)

The only thing I can think of for a single molecule would be to convert to the constituent elements - decomposition?

5Li2O -> 10Li + 5O

sort of a primer for counting all the atoms involved that have to be conserved.

[ - ] localsal 2 points 3.5 yearsDec 6, 2021 23:11:51 ago (+2/-0)

oops, got some hypertext in the answer:

5Li2O (right arrow) 10Li + 5O

[ - ] La_Chalupacabra 1 point 3.5 yearsDec 6, 2021 23:28:27 ago (+1/-0)

You would have 2 O2 and 1 O(-2) radical in that equation.
Also, you may get some use out of this resource: https://www.wolframalpha.com/input/?i=lithium+oxide+reaction

[ - ] stone12345 [op] 1 point 3.5 yearsDec 6, 2021 23:12:23 ago (+1/-0)

Thanks. I think that is what I will do.

[ - ] localsal 1 point 3.5 yearsDec 6, 2021 23:17:58 ago (+1/-0)

If it appears on the exam, I would ask for clarification of how it is a reaction.

But the counting part is pretty important for overall conservation. You could also add the charges, ie, 10Li(+) + 5O(-2) if they became ions.

typically in oxidation and reduction reactions the atoms change from neutral to charged, and then become the molecules.

Another answer beyond just the counting, would be the elemental forms

in this reaction the final results of returning to the base elements would be

5Li2O (right arrow) 10Li + (5/2)O2

since Oxygen never appears as a single atom, it becomes O2 as the molecule.

[ - ] stone12345 [op] 1 point 3.5 yearsDec 6, 2021 23:22:39 ago (+1/-0)

Thank you. You're a life saver.

[ - ] localsal 1 point 3.5 yearsDec 6, 2021 23:23:50 ago (+1/-0)

Don't know if I hit the actual answer they were looking for, just some general reaction notation.

Good luck.

[ - ] stone12345 [op] 1 point 3.5 yearsDec 8, 2021 21:15:46 ago (+1/-0)*

Thank you, also I asked one of my "intellectual" friends and they said that they basically wanted me to expand it, like Li20 + Li20 + Li20 +Li20 + Li20, which is kind of retarded

[ - ] localsal 0 points 3.5 yearsDec 8, 2021 22:27:00 ago (+0/-0)

Does seem that way.

Hopefully every student got that answer right LOL.